Home | Contact Us | FAQ | Search & Site Map | Link to Us
Sign In | Join | Other 45 Sites in Network
Home
DiscussionsAccessExcelInfoPathOutlookPowerPointPublisherWord
DirectoryUser Groups
Related Topics
Outlook ExpressInternet ExplorerWindowsMS Server ProductsMore Topics ...

MS Office Forum / Excel / Charting / November 2003

Tip: Looking for answers? Try searching our database.

Drawing tangents at 10 points

Thread view: 
Enable EMail Alerts  Start New Thread
Thread rating: 
Patts - 27 Nov 2003 00:48 GMT
Hello, How can you draw tangents at 10 different points
in excel. I am using Office 2000. As the gradient at each
tangent, will give me the velocity at that time.

regards
spatts265@yahoo.co.uk
David J. Braden - 27 Nov 2003 06:41 GMT
Do you know the function of the curve? If y9ou can, differentiate it, or
take a central difference: at point x where you want the gradient, use
(f(x+d)-f(x-d))/(2*d), for "small" positive d.
If these don't do the trick, look in this NG a few days back for a similarly
titled post, and responses.

HTH
Dave Braden
.
> Hello, How can you draw tangents at 10 different points
> in excel. I am using Office 2000. As the gradient at each
> tangent, will give me the velocity at that time.
>
> regards
> spatts265@yahoo.co.uk
- 27 Nov 2003 23:48 GMT
Hello, I tried using the polynomial line which goes
through the points of degree 2. But the equation given is
y = -2E-06x2 + 0.0023x + 0.236 which I dont understand.
If I use the method of linest, I am left with y=mx + b, I
can diff but I will not be able to get velocity at each
point as the x would be eliminated once diff.

To be more precise, I have a set of x values which is the
height from 100cm to 190cm. The y values are the time it
takes for the object to fall, in sec.

any other suggestions

regards

>-----Original Message-----
>Do you know the function of the curve? If y9ou can, differentiate it, or
[quoted text clipped - 14 lines]
>
>.
Tushar Mehta - 30 Nov 2003 13:41 GMT
In line.

> Hello, I tried using the polynomial line which goes
> through the points of degree 2. But the equation given is
> y = -2E-06x2 + 0.0023x + 0.236 which I dont understand.

What do you not understand?  I'd hazard a guess that the coefficient of
x^2 is not significant.  Also, to improve on the rounding, double click
the equation and adjust the number of decimal values.

> If I use the method of linest, I am left with y=mx + b, I
> can diff but I will not be able to get velocity at each
> point as the x would be eliminated once diff.

LINEST, contrary to the documentation, works with non-linear equations.  
For one example see Bernard Liengme's
http://www.stfx.ca/people/bliengme/ExcelTips/Polynomial.htm

> To be more precise, I have a set of x values which is the
> height from 100cm to 190cm. The y values are the time it
> takes for the object to fall, in sec.

Huh?  You are plotting t=f(s), not s=f(t), where s is distance and t is
time.  Since the equation of distance as a function of time is
s=1/2*constant-acceleration*t^2 + initial-speed*t + initial distance,
in your case the result is s=1/2*g*t^2, where g is the acceleration due
to gravity.  So, t=Sqrt(2s/g).

> any other suggestions
>
> regards

Signature

Regards,

Tushar Mehta, MS MVP -- Excel
www.tushar-mehta.com
Excel, PowerPoint, and VBA add-ins, tutorials
Custom MS Office productivity solutions

> Hello, I tried using the polynomial line which goes
> through the points of degree 2. But the equation given is
[quoted text clipped - 36 lines]
> >
> >.
 
Sign In
Join
My Latest Posts
My Monitored Threads
My Blog
My Photo Gallery
My Profile
My Homepage

Start New Thread
Enable EMail Alerts
Rate this Thread



©2009 Advenet LLC   Privacy Policy - Terms of Use
This website includes both content owned or controlled by Advenet as well as content owned or controlled by third parties.