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MS Office Forum / Excel / Worksheet Functions / December 2005

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test for "special characters" in text

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Frank Cutre - 20 Dec 2005 18:19 GMT
Hi,

I need to make sure that a cell contains NO SPECIAL CHARACTERS (including
the <SpaceBar>) during data entry.

I've tried:
=len(cellReference)=len(substitute(cellReference,or(char(32),char(34),...etc
),"")

but Excel doesn't like the OR funtion (2nd parameter) inside SUBSTITUTE.

How do you test if a cell reference contains ANY of the "special text
characters" (from list below)?

     space
     double quote
     number
     dollar
     percent
     ampersand
     apostrophe
     open parenthesis
     close parenthesis
     asterisk
     plus
     comma
     hyphen
     period
     forward slash
     colon
     semi-colon
     less than
     equal
     greater than
     at symbol
     open square bracket
     backslash
     close square bracket
     caret
     underscore
     single quote (under tilde)
     open curly bracket
     pipe (above backslash)
     close curly bracket
     tilde

Thanx for your time... (^_^)
CLR - 20 Dec 2005 19:13 GMT
ASAP Utilities, a free Add-in available from www.asap-utilities.com has a
feature called "Advanced Character Removal" that should get rid of any
unwanted characters for you....

Vaya con Dios,
Chuck, CABGx3

> Hi,
>
[quoted text clipped - 43 lines]
>
> Thanx for your time... (^_^)
Tom Ogilvy - 20 Dec 2005 19:22 GMT
Play with something like this array formula:

=MIN(LEN(SUBSTITUTE("ABC#DEFGH",{" ",".","#"},{"","",""})))<Len("ABC#DEFGH")

Signature

Regards,
Tom Ogilvy

> Hi,
>
> I need to make sure that a cell contains NO SPECIAL CHARACTERS (including
> the <SpaceBar>) during data entry.
>
> I've tried:

=len(cellReference)=len(substitute(cellReference,or(char(32),char(34),...etc
> ),"")
>
[quoted text clipped - 36 lines]
>
> Thanx for your time... (^_^)
Frank Cutre - 21 Dec 2005 02:23 GMT
Hi Tom,

ref:
=MIN(LEN(SUBSTITUTE("ABC#DEFGH",{" ",".","#"},{"","",""})))<Len("ABC#DEFGH")

1) This "was" going in a data validation definition (which doesn't like
"arrays") so... how do I get that formula into a VBA udf (which doesn't like
the array formula's "{}" curly brackets)?

and (just for my own info AND when not used in a data validation definition)

2) How do you include the double quote (") character in the "old_text"
parameter of the SUBSTITUTE function?

Thanx for your time... (^_^)

> Play with something like this array formula:
>
[quoted text clipped - 6 lines]
> >
> > I've tried:

=len(cellReference)=len(substitute(cellReference,or(char(32),char(34),...etc
> > ),"")
> >
[quoted text clipped - 36 lines]
> >
> > Thanx for your time... (^_^)
Harlan Grove - 20 Dec 2005 20:01 GMT
Frank Cutre wrote...
>I need to make sure that a cell contains NO SPECIAL CHARACTERS (including
>the <SpaceBar>) during data entry.
>
>I've tried:
>=len(cellReference)=len(substitute(cellReference,or(char(32),char(34),...etc
...
>but Excel doesn't like the OR funtion (2nd parameter) inside SUBSTITUTE.
...

Looks like you want only letters and digits. There's no way to prevent
users from typing them, and if they're clever enough to know how to use
copy & paste, there's no way to use data validation to prevent them
from being entered. That leaves removing them yourself or forcing your
users to remove them.

Doing it yourself, there's no 1-cell way to do it without resorting to
VBA. You could use a udf like the following.

Function foo(s As String, p As String) As String
   Dim c As String * 1, k As Long, n As Long

   n = Len(s)

   For k = 1 To n
       c = Mid$(s, k, 1)
       If c Like p Then foo = foo & c
   Next k

End Function

and use it in formulas like

=foo(B5,"[A-Za-z0-9]")

The other alternative, make your users clean their own entries, can be
done by ensuring that invalid entries trigger nothing but errors in
formula results along with messages that tell the user that it's their
own invalid entries that caused the errors. That can be done with
built-in functions and one defined name, e.g., define the name N
referring to 128 or so, seq referring to

=ROW(INDEX($1:$65536,1,1):INDEX($1:$65536,N,1))

then try the *array* formula

=0/(COUNT(FIND(MID(UPPER(B5),seq,1),
"ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"))=N)

which should return 0 when cell B5 contains nothing but letters and
decimal numerals but #DIV/0! when it contains any other characters.

In my experience nothing is more effective in motivating users to enter
valid data than giving them nothing but errors and diagnostic messages
explaining that those errors are due to invalid entries. If a user can
only print off pages full of errors and text stating that the errors
are their own fault, they can't complain to their bosses or to IT
support. All they can do is fix their own errors. This won't win you
popularity contests among your users, but it will ensure they do what
they're supposed to do.
Ron Rosenfeld - 21 Dec 2005 03:49 GMT
>Hi,
>
[quoted text clipped - 43 lines]
>
>Thanx for your time... (^_^)

If you want to use Data Validation, understanding it's limitations that someone
could copy/paste a value into that cell that did not meet the criteria, then
you could download and install Longre's free morefunc.xll from
http://xcell05.free.fr

If your cell to be validated is, for example, A1, then in some unused cell (for
example Z1) enter the formula:

=REGEX.FIND(A1,"\W")

This will return a 0 UNLESS there is one of your special characters in A1, in
which case it will return the position of that character.

Then use the Data Validation Formula Is:  =Z1=0

--ron
 
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