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MS Office Forum / Excel / Worksheet Functions / August 2006

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RATE v. IRR: which to use?

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nomail1983@hotmail.com - 12 Aug 2006 16:38 GMT
I think this is more of a question about present value concepts and how
to formulate a financial problem than it is about how to use the Excel
functions.  The question was sparked by someone else's inquiry.

Suppose I build something and sell it.  It costs me $2000 to build it,
and the buyer pays me $135 per month for 36 months.  What is my rate of
return?

I thought I could use RATE or IRR equally well.  But the results are
very different.

On the one hand, I might compute RATE(36, 135, -2000, 135*36).  That
produces a monthly rate of 7.59%.  That's the monthly rate at which an
investment of $2000 grows to $4860 over 36 months (verified with FV).

On the other hand, I might compute IRR(A1:A37), where A1 is -2000 and
A2:A37 are 135.  That produces a monthly rate of return of 5.89%.
That's the monthly rate at which the sum of the present values of the
$135 monthly cash flows equals the initial investment of $2000
(verified by summing a column of PV).

Which formulation fits the problem better and why?  That is, what's
wrong with my thinking in one case or the other?

Or did I make a simple mistake in formulation, and once corrected, both
yield the same result?  How?
Martin P - 12 Aug 2006 17:21 GMT
In cell A1 enter -2000 and in all cells from A2 to A37 enter 135.
In some other cell enter the following:
=IRR(A1:A37)
In another cell enter the following:
=RATE(36,-135,2000)
These two should give you the same result.
RATE is for constant payments and IRR can be used for unequal payments. They
happen to be equal in this case.

> I think this is more of a question about present value concepts and how
> to formulate a financial problem than it is about how to use the Excel
[quoted text clipped - 22 lines]
> Or did I make a simple mistake in formulation, and once corrected, both
> yield the same result?  How?
nomail1983@hotmail.com - 12 Aug 2006 17:55 GMT
> In cell A1 enter -2000 and in all cells from A2 to A37 enter 135.
> In some other cell enter the following:  =IRR(A1:A37)
> In another cell enter the following:  =RATE(36,-135,2000)
> These two should give you the same result.

Klunk!  Of course that RATE formulation is equivalent to the IRR
formulation.  Thanks.

But my real question is:  which of the following formulations is the
correct answer to the problem and why?

The problem was:  If I build something at a cost of $2000, and I sell
it for $4860 in payments of $135 over 36 months, what is the monthly
rate of return?

Why is RATE(36,135,-2000) the correct answer instead of
RATE(36,135,-2000,135*36)?
Or is the second formuation the correct answer?  (Surprise!)

On one level, I do believe that the IRR is the correct answer for the
problem; and I do see that the first formulation matches the IRR
formulation.

On another level, I do not see what is wrong with the second way of
thinking, namely that I will have $4860 after 36 months of payments of
$135 and an initial investment of $2000.

Obviously I am having a "brain fart".  Can someone "clear the air" for
me? :-)
Martin P - 12 Aug 2006 18:29 GMT
RATE(36,135,-2000,135*36) would be the formula you would use if you had
135×36 dollars in the 37th month in addition to the all the amounts of 135
dollars that were paid monthly

> > In cell A1 enter -2000 and in all cells from A2 to A37 enter 135.
> > In some other cell enter the following:  =IRR(A1:A37)
[quoted text clipped - 25 lines]
> Obviously I am having a "brain fart".  Can someone "clear the air" for
> me? :-)
nomail1983@hotmail.com - 12 Aug 2006 21:09 GMT
> RATE(36,135,-2000,135*36) would be the formula you would use if you had
> 135×36 dollars in the 37th month in addition to the all the amounts of 135
> dollars that were paid monthly

Right.  Klunk!  Thanks again.
 
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