Ned Help W/ Custom Function

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japorms - 14 Aug 2006 21:29 GMT

Hi Guys,

Im trying to make a custom function but I seem to unable to make the
correct declaration
I have the code below but its not displaying the data that I want

The result should be Lynn Haven for C410 data and ABU for G538. but it
only display 0.

Function Company2(ByRef Company As Integer)
If Company = "C410" Then
Company = "Lynn Haven"
ElseIf Company = "G538" Then
Company = "ABU"
End If
End Function

Can someone help me this?

Thanks!

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japorms

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Ken Johnson - 14 Aug 2006 21:39 GMT

> Hi Guys,
>
[quoted text clipped - 16 lines]
>
> Thanks!

Hi,

Will this work?

Function Company2(ByRef Company As String) as String
If Company = "C410" Then
Company2 = "Lynn Haven"
ElseIf Company = "G538" Then
Company2 = "ABU"
End If
End Function

Ken Johnson

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Toppers - 14 Aug 2006 21:44 GMT

Two errors:

Company should be defined as STRING not INTEGER
Return parameter is function name i.e. COMPANY2 not COMPANY

Function Company2(ByRef Company As String)
If Company = "C410" Then
Company2 = "Lynn Haven"
ElseIf Company = "G538" Then
Company2 = "ABU"
End If
End Function

> Hi Guys,
>
[quoted text clipped - 16 lines]
>
> Thanks!

Reply to this Message

japorms - 14 Aug 2006 21:58 GMT

Thanks! It's now working perfectly.

Toppers Wrote:

> Two errors:
>
[quoted text clipped - 39 lines]
> > View this thread
> http://www.excelforum.com/showthread.php?threadid=571545

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