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MS Office Forum / Excel / Worksheet Functions / August 2006Searching for a value in an Array
I have a master price list were I have in column A the country name, and in column B the machine model number and in column C the price. Obviously you can find the same machine for many countries with different prices, I need a formula were I can extract for a certain country the price of a certain machine. 1 way E2=SUMPRODUCT((A2:A100="usa")*(B2:B100=1)*(C2:C100)) another: put country in D2 and model number in D3 E2=SUMPRODUCT((A2:A100=D2)*(B2:B100=D3)*(C2:C100)) "Farah" skrev: > I have a master price list were I have in column A the country name, and in > column B the machine model number and in column C the price. > Obviously you can find the same machine for many countries with different > prices, I need a formula were I can extract for a certain country the price > of a certain machine. =INDEX(C1:C100,MATCH(1,(A1:A100="country")*(B1:B100="machine"),0)) which is an array formula, it should be committed with Ctrl-Shift-Enter, not just Enter.  SignatureHTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) > I have a master price list were I have in column A the country name, and in > column B the machine model number and in column C the price. > Obviously you can find the same machine for many countries with different > prices, I need a formula were I can extract for a certain country the price > of a certain machine. Bob, I'm getting closer and closer to understanding this stuff, but in this example there is one small piece I haven't got yet, Your Match() has 3 elements: 1) the 1, 2) the combination of the ranges (Col A and ColB as one parameter) 3) the 0, which is an exact match) So 1 (in this case) is the lookup value, hummmm.. not sure I'm getting the meaning here - I take 1 to be the value I'm looking for, confused Tks in Advance, Jim > =INDEX(C1:C100,MATCH(1,(A1:A100="country")*(B1:B100="machine"),0)) > [quoted text clipped - 8 lines] > price > > of a certain machine. Jim, This is matching two values against two ranges. So what it does is compare one value against one range A1:A100="country" which returns an array of TRUE/FALSE values aka the SUMPRODUCT tests that we know and love. Similarly B1:B100="machine" returns another array of TRUE/FALSE. By using the * operator, we coerce them to a single array of 1/0 values. The MATCH statement is then used to find the first 1 within that array, and that index number is passed to the INDEX function to find the matching item in the third range. This technique does assume only a singleton match, it cannot find multiples, it will find the first if multiples exist. But that is no different to VLOOKUP. SignatureHTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) > Bob, > I'm getting closer and closer to understanding this stuff, but in this [quoted text clipped - 23 lines] > > price > > > of a certain machine. ah so; Thanks Bob; So I am looking for (the first) 1 (which is in reality a TRUE); Great - E-X-P-A-N-D-I-N-G- T-H-E M-I-N-D ,,,,, > Jim, > [quoted text clipped - 51 lines] > > > price > > > > of a certain machine. ... which in reality a pair of TRUEs, which equates to the first row that matches both conditions. SignatureHTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) > ah so; > Thanks Bob; So I am looking for (the first) 1 (which is in reality a TRUE); [quoted text clipped - 55 lines] > > > > price > > > > > of a certain machine. Probably it's easier to understand a bit faster version... =INDEX(C1:C100,MATCH(1,IF(A1:A100="country",IF(B1:B100="machine",1)),0)) which still needs to be confirmed with control+shift+enter. > Bob, > I'm getting closer and closer to understanding this stuff, but in this [quoted text clipped - 23 lines] >> price >>> of a certain machine. Guys, It is not working, see I can pass you the files if possible just tell me how as I am new to this whole thing. The point is that I have many machines for one country and I have many countries, to give you an idea, I have seven coutries and for each country and I have more than three hundred machines prices. The system given me a dupm showing in one column the country name and in another column the machine name and then the price. I need a function that checks the country in one column and in the other columnn it checks the machine, if both are OK then it should give me the price which is in another column. Regards, Farah > Probably it's easier to understand a bit faster version... > [quoted text clipped - 29 lines] > >> price > >>> of a certain machine. Which is exactly what we gave you. Did you try it? what happened when you did? SignatureHTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) > Guys, > [quoted text clipped - 44 lines] > > >> price > > >>> of a certain machine. It gave me an error which is #NUM though I checked it many times. The point is that in the countries list, the country is repeated many times, and in the machine model column, the machine is repeated many times, you need to create a lookup function which will search for the machine and then when it founds the machine search in another column for the country and then when both the machine and the country matches your search criteria you need to get the price from another column, which means basically that you have a two columns lookup procedure. Regards, > Which is exactly what we gave you. Did you try it? what happened when you > did? [quoted text clipped - 57 lines] > > > >> price > > > >>> of a certain machine. I completely understand how your data is laid out and the formula I gave you should do what you want. Show me the exact formula that you used. an example of the data would help too. SignatureHTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) > It gave me an error which is #NUM though I checked it many times. The point > is that in the countries list, the country is repeated many times, and in the [quoted text clipped - 31 lines] > > > > > > > Probably it's easier to understand a bit faster version... =INDEX(C1:C100,MATCH(1,IF(A1:A100="country",IF(B1:B100="machine",1)),0)) > > > > which still needs to be confirmed with control+shift+enter. > > > > [quoted text clipped - 30 lines] > > > > >> price > > > > >>> of a certain machine. I attached below the data, I am sorry it is not tidy enough but the first column is the machine model, then you can see the country and then the price. D28886-QS Dewalt Die Grinder. 710W variable speed 13456 IRAQ 137 USD D28886-QS Dewalt Die Grinder. 710W variable speed 13457 JORDAN 137 USD D28886-QS Dewalt Die Grinder. 710W variable speed 13458 LEBANON 137 USD D28886-QS Dewalt Die Grinder. 710W variable speed 13459 SYRIA 137 USD D28886-QS Dewalt Die Grinder. 710W variable speed 13460 EGYPT 137 USD D28886-QS Dewalt Die Grinder. 710W variable speed 13461 LIBYA 126 USD D28886-QS Dewalt Die Grinder. 710W variable speed 13462 MOROCCO 116 EUR D28886-QS Dewalt Die Grinder. 710W variable speed 13463 TUNISIA 134 EUR D28886-QS Dewalt Die Grinder. 710W variable speed 13464 ALGERIA 140.36 USD D51238K-QS USE XJ Version 13457 JORDAN 122.9 USD D51238K-QS USE XJ Version 13458 LEBANON 122.9 USD D51238K-QS USE XJ Version 13459 SYRIA 117 USD D51238K-QS USE XJ Version 13460 EGYPT 122.9 USD D51238K-QS USE XJ Version 13461 LIBYA 125 USD D51238K-QS USE XJ Version 13462 MOROCCO 110 EUR D51238K-QS USE XJ Version 13463 TUNISIA 120 EUR D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13456 IRAQ 132.3 USD D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13457 JORDAN 129 USD D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13458 LEBANON 129 USD D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13459 SYRIA 129 USD D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13460 EGYPT 129 USD D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13461 LIBYA 131.3 USD D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13462 MOROCCO 115.5 EUR D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13464 ALGERIA 139.76 USD D51256K-QS USE XJ VERSION 13456 IRAQ 183.8 USD > I completely understand how your data is laid out and the formula I gave you > should do what you want. [quoted text clipped - 93 lines] > > > > > >> price > > > > > >>> of a certain machine. This works fine for me =INDEX(C1:C100,MATCH(1,(B1:B100="LEBANON")*(A1:A100="D51238K-QS USE XJ Version 13458"),0)) although I do notice that all the machines are unique SignatureHTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) > I attached below the data, I am sorry it is not tidy enough but the first > column is the machine model, then you can see the country and then the price. [quoted text clipped - 122 lines] > > > > > > >> price > > > > > > >>> of a certain machine. Thanks Bob, it is working great, but why do I need to press CTRL+SHIFT+ENTER to evalluate this function Regards, Farah > This works fine for me > [quoted text clipped - 146 lines] > > > > > > > >> price > > > > > > > >>> of a certain machine. Because the double condition test needs to evaluate to an array, and the way that you tell hat to Excel is bey entering with Ctrl-Shift-Enter. SignatureHTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) > Thanks Bob, it is working great, but why do I need to press CTRL+SHIFT+ENTER > to evalluate this function [quoted text clipped - 104 lines] > > > > > > > > > > > > > > > Probably it's easier to understand a bit faster version... =INDEX(C1:C100,MATCH(1,IF(A1:A100="country",IF(B1:B100="machine",1)),0)) > > > > > > > > which still needs to be confirmed with control+shift+enter. > > > > > > > > [quoted text clipped - 28 lines] > > > > > > > > >> > > > > > > > > >> "Farah" <Farah@discussions.microsoft.com> wrote in message news:E3812033-F04C-47D5-9CA2-E8C9459C9EAE@microsoft.com... > > > > > > > > >>> I have a master price list were I have in column A the > > country [quoted text clipped - 10 lines] > > > > > > > > >> price > > > > > > > > >>> of a certain machine. Sorry to jump in here but I have a question that runs along the lines of the original post of this thread but also has a different twist. In each cell of Page 1, A1:100 I want to search Page 2, A1:50 for a specific code. If that code is there then I want the amount in Column B of that same row on Page 2 to be returned. I presume the first part is easily handled by the first part of the INDEX formula below but how do I get it to return the correct value? > Probably it's easier to understand a bit faster version... > [quoted text clipped - 29 lines] > >> price > >>> of a certain machine. |
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