hey,
I`ve excel function
=SEARCH("LV-1";D2)
if search text LV-1 is not found - it returns #VALUE
how can I handle this #VALUE ?
=IF(SEARCH("LV-1";D2);"substring_found";"substring not found")
is not working (#VALUE returned in false case)
I believe this is simple, just cannot think of any solution..
Thanks,
Andis
vezerid - 13 Nov 2006 11:29 GMT
=IF(ISNUMBER(SEARCH("LV-1";D2));"substring_found";"substring not
found")
HTH
Kostis Vezerides
> hey,
>
[quoted text clipped - 14 lines]
> Thanks,
> Andis
Bob Phillips - 13 Nov 2006 11:32 GMT
=IF(ISERROR(SEARCH("LV-1";D2));"substring not found";"substring found")

Signature
HTH
Bob Phillips
(replace somewhere in email address with gmail if mailing direct)
> hey,
>
[quoted text clipped - 14 lines]
> Thanks,
> Andis