I'm just now trying to learn the COUNTIF function but obviously am having a
problem...
If the cell range is (A5:A370) and I need to count the "Y" 's and the "N"
's with the answer resulting in the following format: YYYY/NNNN what would
I use?
Any help apreciated!

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~Christi
Max - 14 Oct 2008 03:16 GMT
=REPT("Y",COUNTIF(A5:A370,"Y"))&"/"&REPT("N",COUNTIF(A5:A370,"N"))

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Max
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> I'm just now trying to learn the COUNTIF function but obviously am having a
> problem...
[quoted text clipped - 4 lines]
>
> Any help apreciated!
ShaneDevenshire - 14 Oct 2008 03:17 GMT
Hi,
Try this:
=COUNTIF(A5:A370,"Y")&"/"&COUNTIF(A5:A370,"N")
However if your really trying to get the ratio
=COUNTIF(A5:A370,"Y")/COUNTIF(A5:A370,"N")
Might be sufficient. You can force the display of as many digits as you
want by using the custom format code:
# ????/????
In this case it would display up to 4 digits/ 4 digits

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Thanks,
Shane Devenshire
> I'm just now trying to learn the COUNTIF function but obviously am having a
> problem...
[quoted text clipped - 4 lines]
>
> Any help apreciated!
Dave Peterson - 14 Oct 2008 03:17 GMT
=rept("y",countif(a5:a370,"y"))&"/"&rept("n",countif(a5:a370,"n"))
You really want:
yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy/nnnnnnnnnnnnnn
or maybe:
=countif(a5:a370,"y")&"/"&countif(a5:a370,"n")
to see something like:
140/139
> I'm just now trying to learn the COUNTIF function but obviously am having a
> problem...
[quoted text clipped - 6 lines]
> --
> ~Christi

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Dave Peterson
Christi - 14 Oct 2008 03:39 GMT
Thanks fella's! I knew this was my best chance. :0)

Signature
~Christi
> =rept("y",countif(a5:a370,"y"))&"/"&rept("n",countif(a5:a370,"n"))
>
[quoted text clipped - 19 lines]
> > --
> > ~Christi
Max - 14 Oct 2008 08:24 GMT
Aha, I focused on this part in your orig. post, wrongly it seems:
> .. with the answer resulting in the following format: YYYY/NNNN

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Max
Singapore
http://savefile.com/projects/236895
Downloads:19,000 Files:362 Subscribers:61
xdemechanik
---