number seperation

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jzamilpa3@yahoo.com - 07 May 2008 15:08 GMT

i have this formula so i can seperate a set of number when needed. for
example a selected amount of diffrent numbers will equal a specific
number. i need to add more to this formula so i can have it
completed.

=IF(OR(--MID(B1,3,3)={31,32,33,34,85,86,139,140,141}),LOOKUP(--
MID(B1,3,1),{1,3,8},{15,12,14}),IF(AND(--MID(B1,3,3)>213,--
MID(B1,3,3)<227),10,IF(OR(--
MID(B1,3,3)={19,21,22,24,25,26,27,28,29,30,35}),13,IF(OR(AND(--
MID(B1,3,3)>145,--MID(B1,3,3)<160),AND(--MID(B1,3,3)>200,--
MID(B1,3,3)<208)),6,IF(OR(AND(--MID(B1,3,3)>62,--
MID(B1,3,3)<79),AND(--MID(B1,3,3)>86,--MID(B1,3,3)<92),AND(--
MID(B1,3,3)>96,--MID(B1,3,3)<136)),11,1+INT((--MID(B1,3,3)-1)/
10))))))

this the set of numbers. the ones on the right have to equal the ones
on the left.
1= 36,44,45,46
3= 37,38,39,54,55
5= 40-43
6= 47,48,49, 146-159, 201-210
7= 23, 83,84, 211
10= 212,214, 227
11= 57-82, 87-136, 163,167, 199, 213
12= 31-34
13= 21,22, 24-30, 160-197
14= 85,86
15= 139-141
16= 1,2,13,14,17,18,53
17= 3,4,15,16,20
19= 50,51,52
20= 19
22= 142-145

thanks for any help provided.

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Mike H. - 07 May 2008 16:39 GMT

This would be a whole lot easier to do if you did it via VBA in code instead
of a formula. You'd have to have the code determine if the cell that was
last changed was one of the "number" cells. Then you'd do your analysis:

if Thatcell=36 then
Thatcell.column+1=1
elseif Thatcell=44 then
Thatcell.column+1=1
etc.....

You should be able to find examples for doing this in other postings. If
not, let me know and I can set you up...

> i have this formula so i can seperate a set of number when needed. for
> example a selected amount of diffrent numbers will equal a specific
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>
> thanks for any help provided.

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jzamilpa3@yahoo.com - 07 May 2008 18:12 GMT

no luck finding what i need. sorry.
i have a database on sheet1 that data is transfered into a diffrent
database on sheet2.
using vba coding.
on a column in sheet2 is where i need the formula or vba to make the
matchup

> This would be a whole lot easier to do if you did it via VBA in code instead
> of a formula. You'd have to have the code determine if the cell that was
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>
> - Show quoted text -

Reply to this Message

Mike H. - 07 May 2008 18:47 GMT

This is quite easy then. In the code when you put the data in sheet2, just
put this code in column x, where x is the column your number goes, assuming
the other number is to the left:

So you have your calculation in your code:

let x=1 'Or start with the new row # only
let Y=the column where the number is
let Z=the column where you want your calculation to go

do while true
if cells(x,y).value=empty then exit do
if cells(x,Y).value=36 or cells(x,y).value=44 or cells(x,y).value=45 or
cells(x,y).value=46 then
let cells(x,z).value=1
elseif cells(x,y).value=37 then '(and the other values for 3)
let cells(x,z).value=3
etc.etc.etc....
end if
x=x+1
Loop

> no luck finding what i need. sorry.
> i have a database on sheet1 that data is transfered into a diffrent
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jzamilpa3@yahoo.com - 08 May 2008 17:32 GMT

i forgot to mention that there are words in tied with the numbers. the
2 letters in front the the number then several words after

> This is quite easy then. In the code when you put the data in sheet2, just
> put this code in column x, where x is the column your number goes, assuming
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>
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Reply to this Message

Mike H. - 08 May 2008 17:46 GMT

No idea what you mean. Please give explicit example so I can follow which
number you're talking about.

> i forgot to mention that there are words in tied with the numbers. the
> 2 letters in front the the number then several words after
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jzamilpa3@yahoo.com - 12 May 2008 13:14 GMT

ok well i have a set of numbers from 1 through 226 and i have broken
them down to a set where they have to equal a set between 1 and 22.

the numbers between 1 and 226 have a pp in front of them always.

pp124
pp23
pp78
pp90

> No idea what you mean. Please give explicit example so I can follow which
> number you're talking about.
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Mike H. - 12 May 2008 13:26 GMT

So in the code I provided before the x=x+1 in the loop, just add this:
if cells(x,y).value>0 and cells(x,y).value<226 then
let cells(x,y).value="pp" & str(cells(x,y).value)
end if

> ok well i have a set of numbers from 1 through 226 and i have broken
> them down to a set where they have to equal a set between 1 and 22.
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John - 12 May 2008 14:52 GMT

I'd be interested in knowing what sort of thing this is your making.
What's it for?

Why can't you use Select Case somehow?

Case pp36,p44,pp45,pp46 : Cells(whatever) = 1
Case pp37,pp38,pp39,pp54,pp55 : Cells(whatever) = 3
and so on

JOhn

> ok well i have a set of numbers from 1 through 226 and i have broken
> them down to a set where they have to equal a set between 1 and 22.
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jzamilpa3@yahoo.com - 12 May 2008 15:15 GMT

its a type of defect of a specific product or products.
there are so many types of defects that one can find (1-226) and from
that it gets narrowed down even more (1-22)

> I'd be interested in knowing what sort of thing this is your making.
> What's it for?
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>
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