1. Enter the following formula into a worksheet cell :-
2. = QUOTIENT (36,16) + RQP
3. Where RQP (=26) is a Named Formula (well defined).
4. The given formula appears to calculate well until the partial
evaluation in the Formula Bar gives #NAME? (that's apparently an error
condition).
5. That means that when the function QUOTIENT is applied in a larger
formula, it would stall thereof.
6. There are inevitably dithering moments at the expense of
troublshooting.
7. Please share your experience. Regards.
What's the definition of RQP?
When I put 26 in a cell and name that cell RQP...
=QUOTIENT(36,16)+RQP returns 28.
***********
Regards,
Ron
XL2002, WinXP-Pro
> 1. Enter the following formula into a worksheet cell :-
>
[quoted text clipped - 13 lines]
>
> 7. Please share your experience. Regards.
tkt_tang@hotmail.com - 28 Dec 2005 04:52 GMT
1. Precisely, RQP = 26 (well defined).
2. The given formula appears to calculate well until the partial
evaluation in the Formula Bar gives #NAME? (that's apparently an error
condition).
3. Thank you.
ScottO - 28 Dec 2005 06:11 GMT
The Quotient function requires that the Analysis ToolPak add-in is
installed.
Go to Tools/Add-ins and click on Analysis ToolPak, then hit OK.
Your formula should now evaluate properly.
Rgds,
ScottO
| 1. Precisely, RQP = 26 (well defined).
|
[quoted text clipped - 3 lines]
|
| 3. Thank you.
tkt_tang@hotmail.com - 28 Dec 2005 06:56 GMT
1. I've dunnit : Go to Tools/Add-ins and click on Analysis ToolPak,
then hit OK.
2. The given formula appears to calculate well ; however, the partial
evaluation in the Formula Bar gives #NAME? (that's apparently an error
condition).
3. Thank you.
Biff - 28 Dec 2005 07:06 GMT
See my other reply.
It appears that the use of the defined name, RQP, also causes what I've
described in my other post.
Biff
> 1. I've dunnit : Go to Tools/Add-ins and click on Analysis ToolPak,
> then hit OK.
[quoted text clipped - 4 lines]
>
> 3. Thank you.
Try this:
Requires that the analysis ToolPak add-in be installed.
A1 = 1/1/2005
A2 = 1/10/2005
Formula:
=NETWORKDAYS(A1,A2)+NETWORKDAYS(A1,A2)
Now, highlight the entire formula in the formula bar then press F9.
Now, highlight the individual functions one at a time and press F9.
If you use Excel XP (2002) or later, select the formula cell and goto
Tools>Formula Auditing>Evaluate Formula. Click the Evaluate button.
> 6. There are inevitably dithering moments at the expense of
> troublshooting.
In the above sceniaro, that's what you might run into. This "feature" was
discussed a while back and the most reasonable conclusion was that a formula
that contains more than 1 function call to the ATP will behave like that.
The formula will work and return a result (not withstanding the typical
errors) but if you ever have to troubleshoot it, it can be a real challenge
depending on the complexity!
In the next version of Excel the ATP functions will be incorporated into the
Excel program itself thus eliminating the add-in.
Biff
> 1. Enter the following formula into a worksheet cell :-
>
[quoted text clipped - 13 lines]
>
> 7. Please share your experience. Regards.
tkt_tang@hotmail.com - 28 Dec 2005 07:53 GMT
Mr. Biff,
1. Thank you for your clarification.
2. A longer formula incorporating Quotient(A,B) stalls (until it's
replaced by INT(A/B)).
3. So kind of you if you could point with a link to : 'This "feature"
was discussed a while back and the most reasonable conclusion was that
a formula that contains more than 1 function call to the ATP will
behave like that.'
4. What's the interim workaround while the world awaits Excel 12 ?
5. Regards.
Biff - 28 Dec 2005 08:09 GMT
See this:
http://tinyurl.com/bzbm5
Biff
> Mr. Biff,
>
[quoted text clipped - 11 lines]
>
> 5. Regards.
Harlan Grove - 28 Dec 2005 18:48 GMT
tkt_tang@hotmail.com wrote...
...
>2. A longer formula incorporating Quotient(A,B) stalls (until it's
>replaced by INT(A/B)).
...
>4. What's the interim workaround while the world awaits Excel 12 ?
Don't screw around using a pointless function like QUOTIENT(x,y). Use
TRUNC(x/y) rather than INT(x/y) if you want the same results as
QUOTIENT when x and y have different signs.
tkt_tang@hotmail.com - 29 Dec 2005 03:46 GMT
Mr. Harlan Grove,
Thank you for your practical suggestion.
Regards.