With the captioned formula in D1;
A1=1, B1=1, C1=nothing; D1=False.
A1=1, B1=2, C1=nothing; D1=True.
A1=1, B1=1, C1=1; D1=False.
A1=1, B1=2, C1=1; D1=False.
A1=nothing, B1=1, C1=1; D1=False.
A1=nothing, B1=1, C1=2; D1=False.
A1=nothing, B1=1, C1=nothing; D1=True.
A1=nothing, B1=nothing, C1=nothing; D1=False.
What is the algorithm being evaluated for this formula?
Thanks,
George
G Lykos - 04 Jul 2006 05:35 GMT
Also, is there a name for this structure of formula (multiple equals)?
Thanks again.
> With the captioned formula in D1;
>
[quoted text clipped - 14 lines]
> Thanks,
> George
Bob Phillips - 04 Jul 2006 08:53 GMT
It is invalid, because it doesn't do what it seems to do. It looks like it
is testing all 3 for the same value, but it is not, it tests A1=B1, which
resolves to TRUE or FALSE, and then tests C1 against that result. Thus if
they all equal 1, A1=B1 resolves to TRUE, but TRUE=1 resolves to FALSE, so
you get FALSE.
You should use
=AND(A1=B1,A1=C1)

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HTH
Bob Phillips
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> With the captioned formula in D1;
>
[quoted text clipped - 14 lines]
> Thanks,
> George