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MS Office Forum / Excel / New Users / November 2006

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Rounding to

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Steven - 24 Nov 2006 21:00 GMT
I have a column of numbers, all multiples of 10, starting at 100 and going
up into the thousands. I want to round them to the nearest 50, so 140 would
become 150 and so would 160. How do I do that?

TIA

Steven

           I plan to live forever.....or die trying!
Bob Phillips - 24 Nov 2006 21:06 GMT
=ROUND(A1/50,0)*50

--

HTH

Bob Phillips

(replace xxxx in the email address with gmail if mailing direct)

> I have a column of numbers, all multiples of 10, starting at 100 and going
> up into the thousands. I want to round them to the nearest 50, so 140 would
[quoted text clipped - 5 lines]
>
>             I plan to live forever.....or die trying!
Steven - 24 Nov 2006 23:43 GMT
Ok, this is a little more complicated than just rounding. Column B has a
figure which is multiplied by column D to get the amount in column F. So
right now, it looks like =B3*D3 and what I need it to do is round that
figure to the nearest 50. So it would be something like
=(B3*D3)=Round(F3,50))? Sorry I did not get this on sooner.

>I have a column of numbers, all multiples of 10, starting at 100 and going
>up into the thousands. I want to round them to the nearest 50, so 140 would
[quoted text clipped - 5 lines]
>
>            I plan to live forever.....or die trying!
Bob Phillips - 25 Nov 2006 00:02 GMT
=ROUND(B3*D3/50,0)*50

--

HTH

Bob Phillips

(replace xxxx in the email address with gmail if mailing direct)

> Ok, this is a little more complicated than just rounding. Column B has a
> figure which is multiplied by column D to get the amount in column F. So
[quoted text clipped - 11 lines]
> >
> >            I plan to live forever.....or die trying!
Steven - 25 Nov 2006 12:21 GMT
That is exactly what I needed, thank you very much.

Steven

> =ROUND(B3*D3/50,0)*50
>
[quoted text clipped - 23 lines]
>> >
>> >            I plan to live forever.....or die trying!
bplumhoff@gmail.com - 28 Nov 2006 12:30 GMT
Hello Steven,

Another solution:
=ROUND(A1*2,-2)/2

HTH,
Bernd

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