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MS Office Forum / Excel / New Users / January 2008avoiding a #value! return
Hi I have a formula ='[Labour Variance Report wk01.xls]Summary'!$N$55+'[Labour Variance Report wk01.xls]Summary'!$N$56='[Labour Variance Report wk01.xls]Summary'!$N$75+'[Labour Variance Report wk01.xls]Summary'!$N $81+'[Labour Variance Report wk01.xls]Summary'!$N$82 some of the referenced cells have a #value! error so I get an error in the returned cell. i want to replace any #value! errors in the above formula with a 0. How do I do this please? Thanks Brian =IF(ISERROR(formula),0,formula)  Signature--- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) > Hi > [quoted text clipped - 11 lines] > > Brian > =IF(ISERROR(formula),0,formula) > [quoted text clipped - 27 lines] > > - Show quoted text - I have applied the formula as above which works a treat. Ta Brian |
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