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MS Office Forum / Excel / General Excel Questions / August 2007

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sonny - 10 Feb 2007 05:41 GMT
Hello, People!
I am looking for a formula that will help me determine how many different
outcome I will get.

I have illusrtated below a simple format the way it will be layed out.

    Home                 Visitor
1.    Tor        vs         Phil
2.    NYI        vs         NYR    
3.    Pitts       vs           NJ
4.    FLA        vs          TB
5.    Cal        vs           EDM
6.    MTL      vs          Ott
7.    Bos       vs          Det
8.    Buf       vs          LA
9.    Van      vs         Nash
10.  NC        vs        Min

Please note the formula that I am looking for:  In game #1 there are two
possible outcomes . Either home team wins or Visitor. The two teams cannot
play the following teams below them or above them. Can any one help me or
guide me to a formula, hopefully with step by step instructions on how to
perform this. I would really appreciate this.
Bernd - 10 Feb 2007 07:15 GMT
2^10 (2^no_of_games)
Equal to the number of different binary numbers up to 10 digits.

Regards,
Bernd
sonny - 10 Feb 2007 19:54 GMT
Thanks Bernd!
Could you provide a little description. I am a little confused on where and
how to input the formula.

Regards

> 2^10 (2^no_of_games)
> Equal to the number of different binary numbers up to 10 digits.
>
> Regards,
> Bernd
Bernd - 10 Feb 2007 20:27 GMT
Hello,

You have 10 games with a possible result of 0 or 1,
so your result universe is
0000000000
0000000001
0000000010
0000000011
0000000100
...
1111111111
That makes 2^10. Just write into any cell
=2^10
which is 1024
Or take my UDF longbin2dec from http://www.sulprobil.com/html/
longdec2bin__.html:
=longbin2dec("10000000000")
which results in 1024 again.

Regards,
Bernd
Sandy Mann - 10 Feb 2007 20:50 GMT
Bernd,

Your link return a *Page not found* for me
Signature

Regards,

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings

sandymann2@mailinator.com
Replace@mailinator.com with @tiscali.co.uk

> Hello,
>
[quoted text clipped - 17 lines]
> Regards,
> Bernd
David Biddulph - 10 Feb 2007 20:58 GMT
I think you've only looked at half of the url, Sandy.  It is:
http://www.sulprobil.com/html/longdec2bin__.html
Signature

David Biddulph

> Bernd,
>
> Your link return a *Page not found* for me

>> Hello,
>>
[quoted text clipped - 17 lines]
>> Regards,
>> Bernd
Bernd - 10 Feb 2007 21:08 GMT
David, Thanks for your help. Regards, Bernd
Sandy Mann - 10 Feb 2007 21:31 GMT
Thank you David.  The link did not seem to be far enough along for it to
have been hit by a line wrap but then there no other*break-point*  Also the
full colon after the 2nd html fooled me into thinking that that line
referred to the text below it.

Signature

Regards,

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings

sandymann2@mailinator.com
Replace@mailinator.com with @tiscali.co.uk

>I think you've only looked at half of the url, Sandy.  It is:
> http://www.sulprobil.com/html/longdec2bin__.html
[quoted text clipped - 24 lines]
>>> Regards,
>>> Bernd
Rubble - 25 Aug 2007 00:12 GMT
Hi Bernd --

Question going beyond your formula -- I am trying to find an additional
formula that looks at how many combinations of 2 digits or 3 digits or so
forth -- so if I had something where I had 5 things then I have 2^5-1 (I
don't use the 00000 in this case) 31 different combos.  What I am trying to
figure out is that I know I have 31 combos, but the 31 combos come from 5
single digits (00001,00010,00100,01000,10000) and a bunch come from 2 digits
(00011,00101, etc).  I am trying to figure out a formula for determining how
many 2 digits combos are possible, how many 1 digits are possible, 3 digits,
etc.

If you know off the top of your head I would appreciate the help --

Thank you --

Jim

> Hello,
>
[quoted text clipped - 17 lines]
> Regards,
> Bernd
David Hilberg - 25 Aug 2007 02:40 GMT
Rubble - Check out Pascal's Triangle. Your answers are in the sixth row.

Alternately,
=COMBIN(5,1)
=COMBIN(5,2)
=COMBIN(5,3)
.
.
.
 - David Hilberg

> Hi Bernd --
>
[quoted text clipped - 35 lines]
>> Regards,
>> Bernd
Rubble - 26 Aug 2007 03:06 GMT
Thank you !!!  That helps me a ton . . . my ability to think through
mathematical formulas has diminished greatly since college -- thank you

> Rubble - Check out Pascal's Triangle. Your answers are in the sixth row.
>
[quoted text clipped - 46 lines]
> >> Regards,
> >> Bernd
David Hilberg - 26 Aug 2007 20:26 GMT
You're welcome. I'm sure it all comes simply *rushing* back to you now!

- David

> Thank you !!!  That helps me a ton . . . my ability to think through
> mathematical formulas has diminished greatly since college -- thank you
[quoted text clipped - 49 lines]
>>>> Regards,
>>>> Bernd
 
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