Hello all,
Currently I am attempting to pull a number from another tab in my workbook
that is a compilation of sub-grouped items. The coding that I was attempting
was:
=SUMIF(Smithfield!A:A,Combined!A14:A23,Smithfield!I:I)
Which will not work due to the multiple criteria. I have also attempted a
SUMPRODUCT code, but because the two arrays are not the same size, a #VALUE
or #NUM value is returned. Let's example here (n is a place holder for any
number):
Smithfield tab:
Col A Col I
5 0
1 20
2 15
2 20
12 0
12 17
3 36
16 52
n etc...
Combined tab:
Col A
12
5
3
7
n
In short, one tab holds all data with multiple groups, another combines like
groups together for a single number. The data on the Combined tab and on the
Smithfield tab can be in any order. As the two arrays A:A and A14:A23 are
not the same size, neither the SUMPRODUCT nor the SUMIF will allow it. I am
looking to pull ONE number as a summation of a group listing (as it is not
the entire list, but a section of it), so if there are 65 groups and I want
to see groups that are listed in the section described (which does not have
to be in a specific order--could be 17,2,5,3,4,22,60,33,etc. in the group I
want to look at), I want to pull one number for the sum of those specified
groups.
Any ideas on how to accomplish this feat?
T. Valko - 16 May 2008 17:13 GMT
Try this:
=SUMPRODUCT(--(ISNUMBER(MATCH(Smithfield!A1:A100,Combined!A14:A23,0))),Smithfield!I1:I100)
Note that with SUMPRODUCT you *can't* use entire columns as range references
unless you're using Excel 2007.

Signature
Biff
Microsoft Excel MVP
> Hello all,
>
[quoted text clipped - 50 lines]
>
> Any ideas on how to accomplish this feat?
Thomas [PBD] - 19 May 2008 13:00 GMT
Works great. MATCH(), haven't seen it before. Will definitely be using that
more often.
> Try this:
>
[quoted text clipped - 57 lines]
> >
> > Any ideas on how to accomplish this feat?
T. Valko - 19 May 2008 17:19 GMT
You're welcome. Thanks for the feedback!

Signature
Biff
Microsoft Excel MVP
> Works great. MATCH(), haven't seen it before. Will definitely be using
> that
[quoted text clipped - 70 lines]
>> >
>> > Any ideas on how to accomplish this feat?