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MS Office Forum / Outlook / Contacts / August 2003

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[Repost] MailingAddressIndicator grouping ?

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Laurent - 25 Jul 2003 00:15 GMT
(Sorry. I posted this two days ago and got no reply. So I repost again in
case  my previous post was left unseen. Thanks for understanding.)

* * *

I would like to group or filter contacts in a way that I can see which
contact has set business, house or other address as the mailing address.

For a start, I set a table view with the MailingAddressIndicator, the
SelectedMailingAddress, the Adress Selector, and the SelectedAdress but it
didn't help much.

-Address selector is a dropdown combobox that display its content only when
selected.

-MailingAddressIndicator is a checkbox that appears only a flick of a
second when selected

-SelectedMailingAddress contents vary too much to be useful as it only
mirrors another address.

-SelectedAddress shows empty and is not editable

I then tried to create a filter based on the Address Selector, thinking
that the Address Indicator combobox index might be a criterion. The rule
was created but the view showed empty. I tried similar technic with the
SelectedAddress, thinking its non-editable content might be something like
0,1, and 2 (index?) or "Home", "Business", and "Other", but it didn't work
either.

I then tought to create a somekind of a rule that would display only
contacts with SelectedMailingAdress = HomeAddress or such thing, but I
don't know how to do that. SQL syntax maybe ?

I dunno

I running out of creative idea.

Anyone can help ?

Thanks.
Henry Mascovitch - 31 Aug 2003 16:15 GMT
microsoft.public.outlook.contacts

> (Sorry. I posted this two days ago and got no reply. So I repost again
> in case  my previous post was left unseen. Thanks for understanding.)
[quoted text clipped - 38 lines]
>
> Thanks.

This question has been asked a number of times (check Google) but nobody
ever gave an answer.

Therefore I understand that the basic thing you want to performe is
impossible. If it is, it would be a pretty much stupid limitation of
Outlook.
 
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