Hi there

I have found that the ChangeFileOpenDirectory command in 2003 is unreliable,
although I have only found one post from someone else about this.  Anyway, in
order to display the File Open dialog screen at a particular path, I write
the (which I successfully collect from another part of the code) as a string
in a text file.  I then collect that path (Folder_Path) and use it in my file
open command as shown below.  This all works fine in various places in the
code.

In one place I need to know whether the user pressed Open of Cancel.  I
believe I need to display, rather than show, the dialog in order to get the
result.  

If I use the following code, it does not open at the correct place:

With Dialogs(wdDialogFileOpen)
   .name = Folder_Path & "\"
   .Format = wdFormatDocument
End With

Result  = Dialogs(wdDialogFileOpen).Display

However, if I use the following code it does work but then I can't get the
result back.

With Dialogs(wdDialogFileOpen)
   .name = Folder_Path & "\"
   .Format = wdFormatDocument
   .Display
End With

Can anyone tell me what I am doing wrong, please?  Or if there is another way
to get the result back?  

Any & all help greatly appreciated.

Many thanks.