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MS Office Forum / Word / Programming / August 2006Bookmark name from PreviousBookmarkID
Word 2003 sp2 I want to return the name of the bookmark preceding the cursor. By analogy with the second example in the VBA Help file entitled "PreviousBookmarkID property", I wrote the following preliminary code: Dim xBookmarkNumber As Long xBookmarkNumber = Selection.PreviousBookmarkID MsgBox xBookmarkNumber MsgBox ActiveDocument.Bookmarks(xBookmarkNumber).Name When I tested this code by placing the cursor after the first bookmark in the document, xBookmarkNumber was identified correctly as 1. However, the name returned by ActiveDocument.Bookmarks(xBookmarkNumber).Name was that of a different bookmark. I finally figured out that the name being returned was the name of the first bookmark IF THE BOOKMARKS ARE SORTED BY NAME!!! Can anybody tell me how to retrieve the name of the previous bookmark? Thanks. PS: I realize that the following code will retrieve the name: MsgBox Selection.Bookmarks(1).Name However, this requires that you select text either surrounding a placeholder bookmark or within an enclosure bookmark, which I don't want to have to take the trouble to do. (And in any case, the code provided in the Help file doesn't work properly!) Odd as it may seem, the syntax ActiveDocument.Bookmarks(xBookmarkNumber) returns the bookmarks in alphabetic order by name, while ActiveDocument.Range.Bookmarks(xBookmarkNumber) returns them in location order. In the Insert > Bookmark dialog, the option buttons for sorting the list by name or by location work exactly the same way. -- Regards, Jay Freedman Microsoft Word MVP FAQ: http://word.mvps.org Email cannot be acknowledged; please post all follow-ups to the newsgroup so all may benefit. >Word 2003 sp2 > [quoted text clipped - 26 lines] >want to have to take the trouble to do. (And in any case, the code >provided in the Help file doesn't work properly!) Excellent. Thanks very much. > Odd as it may seem, the syntax > [quoted text clipped - 46 lines] > >want to have to take the trouble to do. (And in any case, the code > >provided in the Help file doesn't work properly!) |
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