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vbaNOOB - 16 Mar 2007 09:20 GMT

hi all

it's me again
In my vba program, I've created an new regexp called "reg"
the program will match the first paragraph in the active doc using the
reg.test

the program is how should I write the pattern to match "Chapter X"
I try the pattern "Chapter[ ][0-9]"
but it will also match a line like "Chapter 3342545435342543543543"
how should I tell regexp that it's end line??

I've try another like pattern "Chapter[ ][0-9]\n" , pattern "Chapter[
][0-9]^13"
but they cant match anything

many thanks

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Jezebel - 16 Mar 2007 09:52 GMT

You seem to have lost the plot somewhere.

1. [] matches the contents of the brackets -- ie, nothing. It does not match
a single space or any number of spaces.

2. [0-9] matches any ONE digit. It does not match "3342545435342543543543".

I guess the bug in your code is elsewhere

> hi all
>
[quoted text clipped - 13 lines]
>
> many thanks

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Helmut Weber - 16 Mar 2007 13:52 GMT

Hi,

try:

Chapter [0-9]{1,}[^l^13]

\n reminds me of Unix as new line.

It doesn't work in Word.

\ must be followed by a quotable (or control) character,
so to speak, like \ { } [ ] @
though, if it is followed by a non quotable character,
it doesn't rise an error.

See:
http://word.mvps.org/faqs/general/UsingWildcards.htm
http://www.gmayor.com/replace_using_wildcards.htm ' !!

Signature

Greetings from Bavaria, Germany

Helmut Weber, MVP WordVBA

Win XP, Office 2003
"red.sys" & Chr$(64) & "t-online.de"

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Klaus Linke - 16 Mar 2007 20:47 GMT

In case you use the Like operator, try
myParagraph.Range.Text Like ("Chapter [0-9]" & vbCr)

Regards,
Klaus

> hi all
>
[quoted text clipped - 13 lines]
>
> many thanks

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