I don't you can do that with a pure find replace. The problem is that regular
expressions are too limited for operations like that. They deal with strings
and replacing strings, they can not modify what they find in that sens. You
have to use some VBA to fix this. Try recording a find replace in a macro and
go from that.

Of course you can do several search and replace and take each number by
itself.

Hi Alex Wenzel,

I don't think so.

Very probably.

Yes, have a close look at this one:

Sub Test6009()
Dim rDcmn As Range     ' range document
Dim sTmp1 As String    ' temporary string 1
Dim sTmp2 As String    ' temporary string 2
Dim lPstn As Long      ' position in a string
Set rDcmn = ActiveDocument.Range
With rDcmn.Find
  .Text = "\>abc\=([0-9]{1,})\<"
  .MatchWildcards = True
  While .Execute
     sTmp2 = ""
     ' rDcmn.Select
     sTmp1 = rDcmn.Text
     sTmp1 = "#" & Right(sTmp1, Len(sTmp1) - 1)
     lPstn = InStr(sTmp1, "=") + 1
     While IsNumeric(Mid(sTmp1, lPstn, 1))
        sTmp2 = sTmp2 & Mid(sTmp1, lPstn, 1)
        lPstn = lPstn + 1
     Wend
     sTmp2 = CStr(CLng(sTmp2))
     lPstn = InStr(sTmp1, "=")
     sTmp1 = Left(sTmp1, lPstn) & sTmp2 & "#"
     ' msgbox sTmp1
     rDcmn.Text = sTmp1
     rDcmn.Start = rDcmn.End
     rDcmn.End = ActiveDocument.Range.End
  Wend
End With
End Sub

Improvably in many ways.

HTH